Integrand size = 27, antiderivative size = 89 \[ \int \cos ^5(c+d x) \sin (c+d x) (a+a \sin (c+d x))^2 \, dx=-\frac {4 (a+a \sin (c+d x))^5}{5 a^3 d}+\frac {4 (a+a \sin (c+d x))^6}{3 a^4 d}-\frac {5 (a+a \sin (c+d x))^7}{7 a^5 d}+\frac {(a+a \sin (c+d x))^8}{8 a^6 d} \]
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Time = 0.06 (sec) , antiderivative size = 89, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.111, Rules used = {2915, 12, 78} \[ \int \cos ^5(c+d x) \sin (c+d x) (a+a \sin (c+d x))^2 \, dx=\frac {(a \sin (c+d x)+a)^8}{8 a^6 d}-\frac {5 (a \sin (c+d x)+a)^7}{7 a^5 d}+\frac {4 (a \sin (c+d x)+a)^6}{3 a^4 d}-\frac {4 (a \sin (c+d x)+a)^5}{5 a^3 d} \]
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Rule 12
Rule 78
Rule 2915
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {(a-x)^2 x (a+x)^4}{a} \, dx,x,a \sin (c+d x)\right )}{a^5 d} \\ & = \frac {\text {Subst}\left (\int (a-x)^2 x (a+x)^4 \, dx,x,a \sin (c+d x)\right )}{a^6 d} \\ & = \frac {\text {Subst}\left (\int \left (-4 a^3 (a+x)^4+8 a^2 (a+x)^5-5 a (a+x)^6+(a+x)^7\right ) \, dx,x,a \sin (c+d x)\right )}{a^6 d} \\ & = -\frac {4 (a+a \sin (c+d x))^5}{5 a^3 d}+\frac {4 (a+a \sin (c+d x))^6}{3 a^4 d}-\frac {5 (a+a \sin (c+d x))^7}{7 a^5 d}+\frac {(a+a \sin (c+d x))^8}{8 a^6 d} \\ \end{align*}
Time = 0.16 (sec) , antiderivative size = 90, normalized size of antiderivative = 1.01 \[ \int \cos ^5(c+d x) \sin (c+d x) (a+a \sin (c+d x))^2 \, dx=-\frac {a^2 (-2590+10920 \cos (2 (c+d x))+3780 \cos (4 (c+d x))+280 \cos (6 (c+d x))-105 \cos (8 (c+d x))-16800 \sin (c+d x)+1120 \sin (3 (c+d x))+2016 \sin (5 (c+d x))+480 \sin (7 (c+d x)))}{107520 d} \]
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Time = 0.34 (sec) , antiderivative size = 79, normalized size of antiderivative = 0.89
method | result | size |
derivativedivides | \(\frac {a^{2} \left (\frac {\left (\sin ^{8}\left (d x +c \right )\right )}{8}+\frac {2 \left (\sin ^{7}\left (d x +c \right )\right )}{7}-\frac {\left (\sin ^{6}\left (d x +c \right )\right )}{6}-\frac {4 \left (\sin ^{5}\left (d x +c \right )\right )}{5}-\frac {\left (\sin ^{4}\left (d x +c \right )\right )}{4}+\frac {2 \left (\sin ^{3}\left (d x +c \right )\right )}{3}+\frac {\left (\sin ^{2}\left (d x +c \right )\right )}{2}\right )}{d}\) | \(79\) |
default | \(\frac {a^{2} \left (\frac {\left (\sin ^{8}\left (d x +c \right )\right )}{8}+\frac {2 \left (\sin ^{7}\left (d x +c \right )\right )}{7}-\frac {\left (\sin ^{6}\left (d x +c \right )\right )}{6}-\frac {4 \left (\sin ^{5}\left (d x +c \right )\right )}{5}-\frac {\left (\sin ^{4}\left (d x +c \right )\right )}{4}+\frac {2 \left (\sin ^{3}\left (d x +c \right )\right )}{3}+\frac {\left (\sin ^{2}\left (d x +c \right )\right )}{2}\right )}{d}\) | \(79\) |
parallelrisch | \(-\frac {a^{2} \left (3780 \cos \left (4 d x +4 c \right )-14875+10920 \cos \left (2 d x +2 c \right )+1120 \sin \left (3 d x +3 c \right )-16800 \sin \left (d x +c \right )+480 \sin \left (7 d x +7 c \right )+2016 \sin \left (5 d x +5 c \right )-105 \cos \left (8 d x +8 c \right )+280 \cos \left (6 d x +6 c \right )\right )}{107520 d}\) | \(96\) |
risch | \(\frac {5 a^{2} \sin \left (d x +c \right )}{32 d}+\frac {a^{2} \cos \left (8 d x +8 c \right )}{1024 d}-\frac {a^{2} \sin \left (7 d x +7 c \right )}{224 d}-\frac {a^{2} \cos \left (6 d x +6 c \right )}{384 d}-\frac {3 a^{2} \sin \left (5 d x +5 c \right )}{160 d}-\frac {9 a^{2} \cos \left (4 d x +4 c \right )}{256 d}-\frac {a^{2} \sin \left (3 d x +3 c \right )}{96 d}-\frac {13 a^{2} \cos \left (2 d x +2 c \right )}{128 d}\) | \(135\) |
norman | \(\frac {\frac {16 a^{2} \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3 d}+\frac {16 a^{2} \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{15 d}+\frac {1376 a^{2} \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{105 d}+\frac {1376 a^{2} \left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{105 d}+\frac {16 a^{2} \left (\tan ^{11}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{15 d}+\frac {16 a^{2} \left (\tan ^{13}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3 d}+\frac {2 a^{2} \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}+\frac {2 a^{2} \left (\tan ^{14}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}+\frac {8 a^{2} \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}+\frac {8 a^{2} \left (\tan ^{12}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}+\frac {10 a^{2} \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3 d}+\frac {10 a^{2} \left (\tan ^{10}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3 d}+\frac {80 a^{2} \left (\tan ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3 d}}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{8}}\) | \(265\) |
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Time = 0.26 (sec) , antiderivative size = 85, normalized size of antiderivative = 0.96 \[ \int \cos ^5(c+d x) \sin (c+d x) (a+a \sin (c+d x))^2 \, dx=\frac {105 \, a^{2} \cos \left (d x + c\right )^{8} - 280 \, a^{2} \cos \left (d x + c\right )^{6} - 16 \, {\left (15 \, a^{2} \cos \left (d x + c\right )^{6} - 3 \, a^{2} \cos \left (d x + c\right )^{4} - 4 \, a^{2} \cos \left (d x + c\right )^{2} - 8 \, a^{2}\right )} \sin \left (d x + c\right )}{840 \, d} \]
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Time = 0.65 (sec) , antiderivative size = 139, normalized size of antiderivative = 1.56 \[ \int \cos ^5(c+d x) \sin (c+d x) (a+a \sin (c+d x))^2 \, dx=\begin {cases} \frac {16 a^{2} \sin ^{7}{\left (c + d x \right )}}{105 d} + \frac {8 a^{2} \sin ^{5}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{15 d} + \frac {2 a^{2} \sin ^{3}{\left (c + d x \right )} \cos ^{4}{\left (c + d x \right )}}{3 d} - \frac {a^{2} \sin ^{2}{\left (c + d x \right )} \cos ^{6}{\left (c + d x \right )}}{6 d} - \frac {a^{2} \cos ^{8}{\left (c + d x \right )}}{24 d} - \frac {a^{2} \cos ^{6}{\left (c + d x \right )}}{6 d} & \text {for}\: d \neq 0 \\x \left (a \sin {\left (c \right )} + a\right )^{2} \sin {\left (c \right )} \cos ^{5}{\left (c \right )} & \text {otherwise} \end {cases} \]
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Time = 0.22 (sec) , antiderivative size = 97, normalized size of antiderivative = 1.09 \[ \int \cos ^5(c+d x) \sin (c+d x) (a+a \sin (c+d x))^2 \, dx=\frac {105 \, a^{2} \sin \left (d x + c\right )^{8} + 240 \, a^{2} \sin \left (d x + c\right )^{7} - 140 \, a^{2} \sin \left (d x + c\right )^{6} - 672 \, a^{2} \sin \left (d x + c\right )^{5} - 210 \, a^{2} \sin \left (d x + c\right )^{4} + 560 \, a^{2} \sin \left (d x + c\right )^{3} + 420 \, a^{2} \sin \left (d x + c\right )^{2}}{840 \, d} \]
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Time = 0.35 (sec) , antiderivative size = 134, normalized size of antiderivative = 1.51 \[ \int \cos ^5(c+d x) \sin (c+d x) (a+a \sin (c+d x))^2 \, dx=\frac {a^{2} \cos \left (8 \, d x + 8 \, c\right )}{1024 \, d} - \frac {a^{2} \cos \left (6 \, d x + 6 \, c\right )}{384 \, d} - \frac {9 \, a^{2} \cos \left (4 \, d x + 4 \, c\right )}{256 \, d} - \frac {13 \, a^{2} \cos \left (2 \, d x + 2 \, c\right )}{128 \, d} - \frac {a^{2} \sin \left (7 \, d x + 7 \, c\right )}{224 \, d} - \frac {3 \, a^{2} \sin \left (5 \, d x + 5 \, c\right )}{160 \, d} - \frac {a^{2} \sin \left (3 \, d x + 3 \, c\right )}{96 \, d} + \frac {5 \, a^{2} \sin \left (d x + c\right )}{32 \, d} \]
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Time = 9.63 (sec) , antiderivative size = 96, normalized size of antiderivative = 1.08 \[ \int \cos ^5(c+d x) \sin (c+d x) (a+a \sin (c+d x))^2 \, dx=\frac {\frac {a^2\,{\sin \left (c+d\,x\right )}^8}{8}+\frac {2\,a^2\,{\sin \left (c+d\,x\right )}^7}{7}-\frac {a^2\,{\sin \left (c+d\,x\right )}^6}{6}-\frac {4\,a^2\,{\sin \left (c+d\,x\right )}^5}{5}-\frac {a^2\,{\sin \left (c+d\,x\right )}^4}{4}+\frac {2\,a^2\,{\sin \left (c+d\,x\right )}^3}{3}+\frac {a^2\,{\sin \left (c+d\,x\right )}^2}{2}}{d} \]
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